strcasecmp

str_split

Last updated: Fri, 05 Sep 2008

str_word_count

(PHP 4 >= 4.3.0, PHP 5)

str_word_count — 文字列に使用されている単語についての情報を返す

説明

mixed str_word_count ( string $string [, int $format [, string $charlist ]] )

string の単語数を数えます。オプションの format が指定されていない場合、見つかった単語の数を整数値で返します。 format が指定されている場合は結果が配列で返され、配列の内容は format に依存します。 format に設定できる値と対応する出力については以下で示します。

この関数を使用するうえで、'単語' は以下のように定義されます。すなわち、「ロケールに依存しないアルファベットからなる文字列で、その先頭以外の部分に "'" および "-" が含まれていてもよい」。

パラメータ

string

文字列。

format

この関数の戻り値を設定します。現在サポートされている値は以下のとおりです。

0 - 見つかった単語の数を返します。
1 - string の中に見つかった単語を含む配列を返します。
2 - 連想配列を返します。string の中での単語の開始位置がキー、単語自体を対応する値となります。

charlist

'単語' とみなされる文字に追加する文字のリスト。

返り値

選択した format に応じて、配列あるいは整数を返します。

変更履歴

バージョン	説明
5.1.0	`charlist` パラメータが追加されました。

例

例1 str_word_count() の例


<?php

$str = "Hello fri3nd, you're
       looking          good today!";

print_r(str_word_count($str, 1));
print_r(str_word_count($str, 2));
print_r(str_word_count($str, 1, 'àáãç3'));

echo str_word_count($str);

?>

上の例の出力は以下となります。

Array
(
    [0] => Hello
    [1] => fri
    [2] => nd
    [3] => you're
    [4] => looking
    [5] => good
    [6] => today
)

Array
(
    [0] => Hello
    [6] => fri
    [10] => nd
    [14] => you're
    [29] => looking
    [46] => good
    [51] => today
)

Array
(
    [0] => Hello
    [1] => fri3nd
    [2] => you're
    [3] => looking
    [4] => good
    [5] => today
)

7

参考

strcasecmp

str_split

Last updated: Fri, 05 Sep 2008

add a note User Contributed Notes
str_word_count

om+www dot php dot net at miakinen dot net
07-Sep-2008 06:29


Here is a code for a function str_word_count() compatible with UTF-8. I'm sorry that the comments are in French because I am not very good in English: anyway, these comments only try to explain things that are in PCRE or Unicode documentations.



<?php

    /*

     * Explications du masque pour preg_match_all.

     *

     * La fonction str_word_count standard considère qu'un mot est

     * une séquence de caractères qui contient tous les caractères

     * alphabétiques, et qui peut contenir, mais pas commencer

     * par "'" et "-".

     *

     * Avec Unicode et UTF-8, une lettre peut être un caractères

     * ASCII non accentué tel que "e" ou "E", mais aussi un "é" ou

     * un "É", lequel peut se représenter sous la forme de deux

     * caractères : d'abord le "E" non accentué, puis l'accent tout

     * seul. Une lettre "E" ou "É" fait partie de la classe « L »,

     * un accent de la classe « Mn ».

     *

     * Par ailleurs, "-" n'est plus le seul trait d'union possible.

     * Plutôt que de les lister individuellement, j'ai choisi de

     * tester les caractères de la classe « Pd ». Un inconvénient

     * est que cela inclut aussi le tiret cadratin et d'autres,

     * mais cet inconvénient existait déjà avec str_word_count et

     * le tiret ascii, et en outre il ne concerne pas le français

     * (contrairement à l'anglais, il y a toujours des espaces

     * autour de ces tirets).

     *

     * Enfin, "'" n'est pas non plus la seule apostrophe possible.

     * Mais contrairement aux tirets je teste juste l'apostrophe

     * typographique U+2019 à part au lieu de tester la classe « Pf »

     * car cette dernière contient trop de signes de ponctuation

     * à exclure de la définition d'un mot.

     *

     * Un mot commence donc par une lettre \p{L}, éventuellement

     * accentuée (suivie par un nombre quelconque de \p{Mn}), et

     * ensuite on peut rencontrer un nombre quelconques d'autres

     * lettres (\p{L} et \p{Mn}), de tirets (\p{Pd}) ou d'apostrophes

     * (' et \x{2019}). Tout ceci, bien sûr, dans un masque compatible

     * avec UTF-8 (/u à la fin).

     *

     * Pour les références, voir :

     * http://fr2.php.net/manual/fr/regexp.reference.php #regexp.reference.unicode

     * http://fr2.php.net/manual/fr/reference.pcre.pattern.modifiers.php

     */

    define("WORD_COUNT_MASK", "/\p{L}[\p{L}\p{Mn}\p{Pd}'\x{2019}]*/u");



    function str_word_count_utf8($str)

    {

        return preg_match_all(WORD_COUNT_MASK, $str, $matches);

    }

luce
06-Sep-2008 06:52


Fix Cathy function bug.



Original Cathy function :

[code]

<?php

    function limit_text($text, $limit) {

      if (strlen($text) > $limit) {

          $words = str_word_count($text, 2);

          $pos = array_keys($words);

          $text = substr($text, 0, $pos[$limit]) . '...';

      }

      return $text;

    }

?>

[/code]



This function return undefined index if $limit < $text.



For fix it :

[code]

<?php

    function limit_text($text, $limitstr, $limitwrd) {

      if (strlen($text) > $limitstr) {

          $words = str_word_count($text, 2);

          if ($words > $limitwrd) {

              $pos = array_keys($words);

              $text = substr($text, 0, $pos[$limitwrd]) . '...';

          }

      }

      return $text;

    }

?>

[/code]

aspu.ru
17-Jun-2008 08:21


str_word_count: mixed (string string, [int format], [string charlist])



It can help you to solve problem with digest and some locales. Best regards.

robocop at robotix dot fr
30-Mar-2008 11:21


function count_words($texte)

{

$texte=trim($texte);

$motsinutiles = array(' * ', ' - ', ' : ', '\n');

$texte = str_replace($motsinutiles, '', $texte);

$texte = preg_replace("/\s\s+/", " ", $texte);

$decoupeapostrophes = count(explode('\'', $texte)); //On découpe la chaine en apostrophes

   if($decoupeapostrophes==0) $nombreapostrophes = 0;

   if ($decoupeapostrophes%2==0) {$nombreapostrophes = $decoupeapostrophes/2;}

   else  $nombreapostrophes = ($decoupeapostrophes/2)-0.5;

$nombreespace = count(explode(' ', $texte));



return $nombreespace+$nombreapostrophes;    

}

security_man
25-Dec-2007 06:13


there was a glitch in the code cathy put a post or two ago... should be:



    function limit_text($text, $limit) {

    $text = strip_tags($text);

      $words = str_word_count($text, 2);

      $pos = array_keys($words);

      if (count($words) > $limit) {

          $text = substr($text, 0, $pos[$limit]) . ' ...';

      }

    return $text;

    }



I also added the strip tags in case there is html in there to gum up the works

Adeel Khan
09-Dec-2007 01:01


<?php



/**

 * Returns the number of words in a string.

 * As far as I have tested, it is very accurate.

 * The string can have HTML in it,

 * but you should do something like this first:

 *

 *    $search = array(

 *      '@<script[^>]*?>.*?</script>@si',

 *      '@<style[^>]*?>.*?</style>@siU',

 *      '@<![\s\S]*?--[ \t\n\r]*>@'

 *    );

 *    $html = preg_replace($search, '', $html);

 *

 */



function word_count($html) {



  # strip all html tags

  $wc = strip_tags($html);



  # remove 'words' that don't consist of alphanumerical characters or punctuation

  $pattern = "#[^(\w|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-|:|\&|@)]+#";

  $wc = trim(preg_replace($pattern, " ", $wc));



  # remove one-letter 'words' that consist only of punctuation

  $wc = trim(preg_replace("#\s*[(\'|\"|\.|\!|\?|;|,|\\|\/|\-|:|\&|@)]\s*#", " ", $wc));



  # remove superfluous whitespace

  $wc = preg_replace("/\s\s+/", " ", $wc);



  # split string into an array of words

  $wc = explode(" ", $wc);



  # remove empty elements

  $wc = array_filter($wc);



  # return the number of words

  return count($wc);



}



?>

Cathy
20-Jul-2007 05:16


A cute little function for truncating text to a given word limit:

<?php

    function limit_text($text, $limit) {

      if (strlen($text) > $limit) {

          $words = str_word_count($text, 2);

          $pos = array_keys($words);

          $text = substr($text, 0, $pos[$limit]) . '...';

      }

      return $text;

    }

?>

geertdd at gmail dot com
14-Jun-2007 01:04


This is an update to my previously posted word_limiter() function. The regex is even more optimized now. Just replace the preg_match line. Change to:



<?php

preg_match('/^\s*(?:\S+\s*){1,'. (int) $limit .'}/', $str, $matches);

geertdd at gmail dot com
28-May-2007 08:52


Here's a very fast word limiter function that preserves the original whitespace.



<?php



function word_limiter($str, $limit = 100, $end_char = '&#8230;') {

    

    if (trim($str) == '')

        return $str;

    

    preg_match('/\s*(?:\S*\s*){'. (int) $limit .'}/', $str, $matches);



    if (strlen($matches[0]) == strlen($str))

        $end_char = '';



    return rtrim($matches[0]) . $end_char;

}



?>



For the thought process behind this function, please read: http://codeigniter.com/forums/viewthread/51788/



Geert De Deckere

joshua dot blake at gmail dot com
03-Mar-2007 10:02


I needed a function which would extract the first hundred words out of a given input while retaining all markup such as line breaks, double spaces and the like. Most of the regexp based functions posted above were accurate in that they counted out a hundred words, but recombined the paragraph by imploding an array down to a string. This did away with any such hopes of line breaks, and thus I devised a crude but very accurate function which does all that I ask it to:



function Truncate($input, $numWords) 

{

  if(str_word_count($input,0)>$numWords)

  {

    $WordKey = str_word_count($input,1);

    $PosKey = str_word_count($input,2);

    reset($PosKey);

    foreach($WordKey as $key => &$value)

    {

        $value=key($PosKey);

        next($PosKey);

    }

    return substr($input,0,$WordKey[$numWords]);

  }

  else {return $input;}

}



The idea behind it? Go through the keys of the arrays returned by str_word_count and associate the number of each word with its character position in the phrase. Then use substr to return everything up until the nth character. I have tested this function on rather large entries and it seems to be efficient enough that it does not bog down at all.



Cheers!



Josh

josh at joshblake.net
02-Mar-2007 08:57


I was interested in a function which returned the first few words out of a larger string.



In reality, I wanted a preview of the first hundred words of a blog entry which was well over that.



I found all of the other functions which explode and implode strings to arrays lost key markups such as line breaks etc.



So, this is what I came up with:



function WordTruncate($input, $numWords) {

if(str_word_count($input,0)>$numWords)

{

    $WordKey = str_word_count($input,1);

    $WordIndex = array_flip(str_word_count($input,2));

    return substr($input,0,$WordIndex[$WordKey[$numWords]]);

}

else {return $input;}

}



While I haven't counted per se, it's accurate enough for my needs. It will also return the entire string if it's less than the specified number of words.



The idea behind it? Use str_word_count to identify the nth word, then use str_word_count to identify the position of that word within the string, then use substr to extract up to that position.



Josh.

31-Jan-2007 01:15


Here is a php work counting function together with a javascript version which will print the same result.



<?php

      //Php word counting function

      function word_count($theString)

      {

        $char_count = strlen($theString);

        $fullStr = $theString." ";

        $initial_whitespace_rExp = "^[[:alnum:]]$";

        

        $left_trimmedStr = ereg_replace($initial_whitespace_rExp,"",$fullStr);

        $non_alphanumerics_rExp = "^[[:alnum:]]$";

        $cleanedStr = ereg_replace($non_alphanumerics_rExp," ",$left_trimmedStr);

        $splitString = explode(" ",$cleanedStr);

        

        $word_count = count($splitString)-1;

        

        if(strlen($fullStr)<2)

        {

          $word_count=0;

        }      

        return $word_count;

      }

?>



<?php

      //Function to count words in a phrase

      function wordCount(theString)

      {

        var char_count = theString.length;

        var fullStr = theString + " ";

        var initial_whitespace_rExp = /^[^A-Za-z0-9]+/gi;

        var left_trimmedStr = fullStr.replace(initial_whitespace_rExp, "");

        var non_alphanumerics_rExp = rExp = /[^A-Za-z0-9]+/gi;

        var cleanedStr = left_trimmedStr.replace(non_alphanumerics_rExp, " ");

        var splitString = cleanedStr.split(" ");

        

        var word_count = splitString.length -1;

        

        if (fullStr.length <2) 

        {

          word_count = 0;

        }      

        return word_count;

      }

?>

Aurelien Marchand
07-Oct-2006 01:06


I found a more reliable way to print, say the first 100 words and then print elipses. My code goes this way;



$threshold_length = 80; // 80 words max

$phrase = "...."; // populate this with the text you want to display

$abody = str_word_count($phrase,2);

if(count($abody) >= $threshold_length){ // gotta cut

  $tbody = array_keys($abody);

  echo "<p>" . substr($phrase,0,$tbody[$threshold_length]) . "... <span class=\"more\"><a href=\"?\">read more</a></span> </p>\n";

} else { // put the whole thing

  echo "<p>" . $phrase . "</p>\n";

}



For any questions, com.iname@artaxerxes2

lwright at psu dot edu
18-Aug-2006 03:51


If you are looking to count the frequency of words, try:



<?php



$wordfrequency = array_count_values( str_word_count( $string, 1) );



?>

rabin at rab dot in
05-Apr-2006 03:03


There is a small bug in the "trim_text" function by "webmaster at joshstmarie dot com" below. If the string's word count is lesser than or equal to $truncation, that function will cut off the last word in the string.





[EDITOR'S NOTE: above referenced note has been removed]





This fixes the problem:





<?php


function trim_text_fixed($string, $truncation = 250) {


    $matches = preg_split("/\s+/", $string, $truncation + 1);


    $sz = count($matches);


    if ( $sz > $truncation ) {


        unset($matches[$sz-1]);


        return implode(' ',$matches);


    }


    return $string;


}


?>

webmaster at joshstmarie dot com
26-Sep-2005 08:58


Trying to make an effiecient word splitter, and "paragraph limiter", eg, limit item text to 100, or 200 words and so-forth.



I don't know how well this compares, but it works nicely.



function trim_text($string, $word_count=100)

{

    $trimmed = "";

    $string = preg_replace("/\040+/"," ", trim($string));

    $stringc = explode(" ",$string);

    echo sizeof($stringc);

    if($word_count >= sizeof($stringc))

    {

        // nothing to do, our string is smaller than the limit.

      return $string;

    }

    elseif($word_count < sizeof($stringc))

    {

        // trim the string to the word count

        for($i=0;$i<$word_count;$i++)

        {

            $trimmed .= $stringc[$i]." ";

        }

        

        if(substr($trimmed, strlen(trim($trimmed))-1, 1) == '.')

          return trim($trimmed).'..';

        else

          return trim($trimmed).'...';

    }

}



$text = "some  test          text goes in here, I'm not sure, but ok.";

echo trim_text($text,5);

MadCoder
16-Aug-2005 01:12


Here's a function that will trim a $string down to a certian number of words, and add a...   on the end of it.

(explansion of muz1's 1st 100 words code)



----------------------------------------------

function trim_text($text, $count){

$text = str_replace("  ", " ", $text);

$string = explode(" ", $text);

for ( $wordCounter = 0; $wordCounter <= $count;wordCounter++ ){ 

$trimed .= $string[$wordCounter];

if ( $wordCounter < $count ){ $trimed .= " "; }

else { $trimed .= "..."; }

}

$trimed = trim($trimed);

return $trimed;

}



Usage

------------------------------------------------

$string = "one two three four";

echo trim_text($string, 3);



returns:

one two three...

jtey at uoguelph dot ca
15-Aug-2005 08:21


In the previous note, the example will only extract from the string, words separated by exactly one space.  To properly extract words from all strings, use regular expressions.



Example (extracting the first 4 words):

<?php

$string = "One    two three       four  five six";

echo implode(" ", array_slice(preg_split("/\s+/", $string), 0, 4));

?>



The above $string would not have otherwise worked when using the explode() method below.

jtey at uoguelph dot ca
14-Aug-2005 11:59


In reply to muz1's post below:



You can also take advantage of using other built in PHP functions to get to your final result.  Consider the following:

<?php

$string = "One two three four five six seven eight nine ten.";

// the first n words to extract

$n = 3;

// extract the words

$words = explode(" ", $string);

// chop the words array down to the first n elements

$firstN = array_slice($words, 0, $n);

// glue the 3 elements back into a spaced sentence

$firstNAsAString = implode(" ", $firstN);

// display it

echo $firstNAsAString;

?>



Or to do it all in one line:

<?php

echo implode(" ", array_slice(explode(" ", $string), 0, $n));

?>

muz1 at muzcore dot com
12-Aug-2005 04:56


This function is awesome however I needed to display the first 100 words of a string. I am submitting this as a possible solution but also to get feedback as to whether it is the most efficient way of doing it.



<?

                                    $currString = explode(" ", $string);

for ($wordCounter=0; $wordCounter<100; $wordCounter++) { echo $currString[$wordCounter]." "; }

?>

16-Jan-2005 11:38


This function seems to view numbers as whitespace. I.e. a word consisting of numbers only won't be counted.

aix at lux dot ee
14-Nov-2004 07:53


One function.

<?php

if (!function_exists('word_count')) {

function word_count($str,$n = "0"){

    $m=strlen($str)/2;

    $a=1;

    while ($a<$m) {

        $str=str_replace("  "," ",$str);

        $a++;

        }

    $b = explode(" ", $str);

    $i = 0; 

    foreach ($b as $v) {

        $i++;

        }

    if ($n==1) return $b;

    else  return $i;



    }

}

$str="Tere Tartu linn";

$c  = word_count($str,1); // it return an array

$d  = word_count($str); // it return int - how many words was in text

print_r($c);

echo $d;

?>

aidan at php dot net
26-Jun-2004 07:02


This functionality is now implemented in the PEAR package PHP_Compat.



More information about using this function without upgrading your version of PHP can be found on the below link:



http://pear.php.net/package/PHP_Compat

Kirils Solovjovs
23-Feb-2004 02:06


Nothing of this worked for me. I think countwords() is very encoding dependent. This is the code for win1257. For other layots you just need to redefine the ranges of letters...



<?php

function countwords($text){

        $ls=0;//was it a whitespace?

        $cc33=0;//counter

        for($i=0;$i<strlen($text);$i++){

                $spstat=false; //is it a number or a letter?

                $ot=ord($text[$i]);

                if( (($ot>=48) && ($ot<=57)) ||  (($ot>=97) && ($ot<=122)) || (($ot>=65) && ($ot<=90)) || ($ot==170) ||

                (($ot>=192) && ($ot<=214)) || (($ot>=216) && ($ot<=246)) || (($ot>=248) && ($ot<=254))  )$spstat=true;

                if(($ls==0)&&($spstat)){

                        $ls=1;

                        $cc33++;

                }

                if(!$spstat)$ls=0;

        }

        return $cc33;

}



?>

Artimis
15-Oct-2003 06:32


Never use this function to count/separate alphanumeric words, it will just split them up words to words, numbers to numbers.  You could refer to another function "preg_split" when splitting alphanumeric words.  It works with Chinese characters as well.

andrea at 3site dot it
19-May-2003 08:55


if string doesn't contain the space " ", the explode method doesn't do anything, so i've wrote this and it seems works better ... i don't know about time and resource





<?php


function str_incounter($match,$string) {


$count_match = 0;


for($i=0;$i<strlen($string);$i++) {


if(strtolower(substr($string,$i,strlen($match)))==strtolower($match)) {


$count_match++;


}


}


return $count_match;


}


?>





example 





<?php


$string = "something:something!!something";


$count_some = str_incounter("something",$string);


// will return 3


?>

megat at megat dot co dot uk
19-Apr-2003 10:29


[Ed: You'd probably want to use regular expressions if this was the case --alindeman @ php.net]





Consider what will happen in some of the above suggestions when a person puts more than one space between words. That's why it's not sufficient just to explode the string.

olivier at ultragreen dot net
11-Apr-2003 10:10


I will not discuss the accuracy of this function but one of the source codes above does this.





<?php


function wrdcnt($haystack) {


 $cnt = explode(" ", $haystack);


 return count($cnt) - 1;


}


?>





That could be replace by 





<?php


function wrdcnt($haystack) {


 return substr_count($haystack,' ') + 1;


}


?>





I doubt this does need to be a function :)

philip at cornado dot com
07-Apr-2003 11:30


Some ask not just split on ' ', well, it's because simply exploding on a ' ' isn't fully accurate.  Words can be separated by tabs, newlines, double spaces, etc.  This is why people tend to seperate on all whitespace with regular expressions.

rcATinterfacesDOTfr
17-Jan-2003 12:58


Here is another way to count words :

$word_count = count(preg_split('/\W+/', $text, -1, PREG_SPLIT_NO_EMPTY));

brettNOSPAM at olwm dot NO_SPAM dot com
10-Nov-2002 05:06


This example may not be pretty, but It proves accurate:





<?php


//count words


$words_to_count = strip_tags($body);


$pattern = "/[^(\w|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-\-|:|\&|@)]+/";


$words_to_count = preg_replace ($pattern, " ", $words_to_count);


$words_to_count = trim($words_to_count);


$total_words = count(explode(" ",$words_to_count));


?>





Hope I didn't miss any punctuation. ;-)

gorgonzola at nospam dot org
01-Nov-2002 07:48


i tried to write a wordcounter and ended up with this:





<?php


//strip html-codes or entities


$text = strip_tags(strtr($text, array_flip(get_html_translation_table(HTML_ENTITIES))));


//count the words


$wordcount = preg_match_all("#(\w+)#", $text, $match_dummy );


?>

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strcasecmp

str_split

Last updated: Fri, 05 Sep 2008